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PrSS VS 康托范式

来自Googology Wiki
Z留言 | 贡献2025年7月5日 (六) 07:27的版本

本条目展示PrSS康托范式的列表分析

(0)=1

(0,0)=2

(0,0,0)=3

(0,1)=(0,0,,0)=ω

(0,1,0)=ω+1

(0,1,0,0)=ω+2

(0,1,0,1)=(0,1,0,0,,0)=ω×2

(0,1,0,1,0,1)=ω×3

(0,1,1)=(0,1,0,1,,0,1)=ω2

(0,1,1,0)=ω2+1

(0,1,1,0,1)=ω2+ω

(0,1,1,0,1,0)=ω2+ω+1

(0,1,1,0,1,0,1)=ω2+ω×2

(0,1,1,0,1,1)=(0,1,1,0,1,0,1,,0,1)=ω2×2

(0,1,1,0,1,1,0,1,1)=ω2×3

(0,1,1,1)=(0,1,1,0,1,1,,0,1,1)=ω3

(0,1,1,1,1)=ω4

(0,1,2)=(0,1,1,,1)=ωω

(0,1,2,0,1,2)=ωω×2

(0,1,2,1)=(0,1,2,0,1,2,,0,1,2)=ωω+1

(0,1,2,1,0,1,2)=ωω+1+ωω

(0,1,2,1,0,1,2,1)=ωω+1×2

(0,1,2,1,1)=(0,1,2,1,0,1,2,1,,0,1,2,1)=ωω+2

(0,1,2,1,1,1)=ωω+3

(0,1,2,1,2)=(0,1,2,1,1,,1)=ωω×2

(0,1,2,1,2,1)=ωω×2+1

(0,1,2,1,2,1,2)=ωω×3

(0,1,2,2)=(0,1,2,1,2,,1,2)=ωω2

(0,1,2,2,1)=ωω2+1

(0,1,2,2,1,2)=ωω2+ω

(0,1,2,2,1,2,1)=ωω2+ω+1

(0,1,2,2,1,2,1,2)=ωω2+ω×2

(0,1,2,2,1,2,2)=(0,1,2,2,1,2,1,2,,1,2)=ωω2*2

(0,1,2,2,2)=(0,1,2,2,1,2,2,,1,2,2)=ωω3

(0,1,2,3)=(0,1,2,2,,2)=ωωω

(0,1,2,3,2)=ωωω+1

(0,1,2,3,2,3)=ωωω×2

(0,1,2,3,3)=ωωω2

(0,1,2,3,4)=(0,1,2,3,3,,3)=ωωωω

(0,1,2,3,4,5,...)=Limit of PrSS=ε0

最终得到,PrSS的极限是ε0.