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strong fffz分析Part1

来自Googology Wiki
Alice留言 | 贡献2026年8月2日 (日) 14:41的版本

ψZ(0)=1

ψZ[1](1)=2

ψZ[1](ψZ[1](1))=3

ψZ(1)=ω

ψZ[2](2)=ω+1

ψZ[2](ψZ(1))=ω×2

ψZ[2](ψZ[2](2))=ω×2+1

ψZ(2)=ω2

ψZ[ω](ω)=ωω

ψZ[ω](ω+1)=ωω+1

ψZ[ω](ω2)=ωω2

ψZ[ω](ψZ[ω](ω))=ωωω

ψZ(ω)=(0)(1,1)

ψZ(ω+1)=(0)(1,1)(1)

ψZ[ω×2](ω×2)=(0)(1,1)(1)(2)

ψZ[ω×2](ωω)=(0)(1,1)(1)(2)(3)

ψZ[ω×2](ψZ(ω))=(0)(1,1)(1)(2,1)

ψZ[ω×2](ψZ[ω×2](ω×2))=(0)(1,1)(1)(2,1)(2)(3)

ψZ(ω×2)=(0)(1,1)(1,1)

ψZ[ω2](ω2)=(0)(1,1)(2)

ψZ[ω2,ω2+ω](ω2+ω)=(0)(1,1)(2)(1)(2)

ψZ[ω2](ω2+ω)=(0)(1,1)(2)(1,1)

ψZ[ω2](ω2×2)=(0)(1,1)(2)(1,1)(2)

ψZ[ω2](ω3)=(0)(1,1)(2)(2)

ψZ[ω2,ωω](ωω)=(0)(1,1)(2)(3)

ψZ[ω2,ωω,ωω+ω](ωω+ω)=(0)(1,1)(2)(3)(1)(2)

ψZ[ω2,ωω](ωω+ω)=(0)(1,1)(2)(3)(1,1)

ψZ[ω2,ωω](ωω×2)=(0)(1,1)(2)(3)(1,1)(2)(3)

ψZ[ω2,ωω](ωω+1)=(0)(1,1)(2)(3)(2)

ψZ[ω2,ωω](ωω×2)=(0)(1,1)(2)(3)(2)(3)

ψZ[ω2,ωω](ωω2)=(0)(1,1)(2)(3)(3)

ψZ[ω2,ωω](ωωω)=(0)(1,1)(2)(3)(4)

ψZ[ω2,ωω](ψZ(ω))=(0)(1,1)(2)(3,1)

ψZ[ω2,ωω](ψZ(ω)+ω)=(0)(1,1)(2)(3,1)(1,1)

ψZ[ω2,ωω](ψZ(ω+1))=(0)(1,1)(2)(3,1)(2)

ψZ[ω2,ωω](ψZ[ω×2](ω×2))=(0)(1,1)(2)(3,1)(2)(3)

ψZ[ω2,ωω](ψZ[ω×2](ψZ(ω)))=(0)(1,1)(2)(3,1)(2)(3,1)

ψZ[ω2,ωω](ψZ[ω×2](ψZ(ω+1)))=(0)(1,1)(2)(3,1)(3)

ψZ[ω2,ωω](ψZ(ω×2))=(0)(1,1)(2)(3,1)(3,1)

ψZ[ω2,ωω](ψZ[ω2,ωω](ωω))=(0)(1,1)(2)(3,1)(4)(5)

ψZ[ω2](ωω)=(0)(1,1)(2,1)

ψZ[ω2](ωω+ω)=(0)(1,1)(2,1)(1,1)

ψZ[ω2,ωω×2](ωω×2)=(0)(1,1)(2,1)(1,1)(2)(3)

ψZ[ω2](ωω×2)=(0)(1,1)(2,1)(1,1)(2,1)

ψZ[ω2](ωω+1)=(0)(1,1)(2,1)(2)

ψZ[ω2](ωω+1+ωω)=(0)(1,1)(2,1)(2)(1,1)(2,1)

ψZ[ω2](ωω+2)=(0)(1,1)(2,1)(2)(2)

ψZ[ω2,ωω×2](ωω×2)=(0)(1,1)(2,1)(2)(3)

ψZ[ω2,ωω×2](ψZ(ω))=(0)(1,1)(2,1)(2)(3,1)

ψZ[ω2,ωω×2](ψZ[ω2,ωω×2](ωω×2))=(0)(1,1)(2,1)(2)(3,1)(4,1)(4)(5)

ψZ[ω2](ωω×2)=(0)(1,1)(2,1)(2,1)

ψZ[ω2](ωω2)=(0)(1,1)(2,1)(3)

ψZ[ω2](ωω2+ω)=(0)(1,1)(2,1)(3)(2,1)

ψZ[ω2](ωω3)=(0)(1,1)(2,1)(3)(3)

ψZ[ω2,ωωω](ωωω)=(0)(1,1)(2,1)(3)(4)

ψZ[ω2,ωωω,ωωω+ω](ωωω+ω)=(0)(1,1)(2,1)(3)(4)(2)(3)

ψZ[ω2,ωωω](ωωω+ω)=(0)(1,1)(2,1)(3)(4)(2,1)

ψZ[ω2,ωωω](ψZ(ω))=(0)(1,1)(2,1)(3)(4,1)

ψZ[ω2,ωωω](ψZ[ω2,ωωω](ωωω))=(0)(1,1)(2,1)(3)(4,1)(5,1)(6)(7)

ψZ[ω2](ωωω)=(0)(1,1)(2,1)(3,1)

ψZ[ω2,ωωω+ω](ωωω+ω)=(0)(1,1)(2,1)(3,1)(2)(3)

ψZ[ω2,ωωω+ω,ωωω+ω+ωωω](ωωω+ω+ωωω)=(0)(1,1)(2,1)(3,1)(2)(3)(1,1)(2,1)(3)(4)

ψZ[ω2,ωωω+ω](ωωω+ω+ωωω)=(0)(1,1)(2,1)(3,1)(2)(3)(1,1)(2,1)(3,1)

ψZ[ω2](ωωω+ω)=(0)(1,1)(2,1)(3,1)(2,1)

ψZ[ω2](ωωω+1)=(0)(1,1)(2,1)(3,1)(3)

ψZ[ω2](ωωω×2)=(0)(1,1)(2,1)(3,1)(3,1)

ψZ[ω2](ωωω2)=(0)(1,1)(2,1)(3,1)(4)

ψZ[ω2,ωωωω](ωωωω)=(0)(1,1)(2,1)(3,1)(4)(5)

ψZ[ω2](ωωωω)=(0)(1,1)(2,1)(3,1)(4,1)

ψZ[ω2](ψZ(ω))=(0)(1,1)(2,2)

ψZ[ω2](ψZ(ω)+ω)=(0)(1,1)(2,2)(1,1)

ψZ[ω2](ψZ(ω)×2)=(0)(1,1)(2,2)(1,1)(2,2)

ψZ[ω2](ψZ(ω+1))=(0)(1,1)(2,2)(2)

ψZ[ω2](ψZ(ω+1)+ψZ(ω))=(0)(1,1)(2,2)(2)(1,1)(2,2)

ψZ[ω2](ψZ(ω+2))=(0)(1,1)(2,2)(2)(2)

ψZ[ω2,ψZ[ω×2](ω×2)](ψZ[ω×2](ω×2))=(0)(1,1)(2,2)(2)(3)

ψZ[ω2,ψZ[ω×2](ω×2)](ψZ(ω×2))=(0)(1,1)(2,2)(2)(3,1)

ψZ[ω2,ψZ[ω×2](ω×2)](ψZ[ω2,ψZ[ω×2](ω×2)](ψZ[ω×2](ω×2)))=(0)(1,1)(2,2)(2)(3,1)(4,2)(4)(5)

ψZ[ω2](ψZ[ω×2](ω×2))=(0)(1,1)(2,2)(2,1)

ψZ[ω2](ψZ[ω×2](ω×2+1))=(0)(1,1)(2,2)(2,1)(2)

ψZ[ω2,ψZ[ω×2](ω×3)](ψZ[ω×2](ω×3))=(0)(1,1)(2,2)(2,1)(2)(3)

ψZ[ω2](ψZ[ω×2](ω×3))=(0)(1,1)(2,2)(2,1)(2,1)

ψZ[ω2](ψZ[ω×2](ω2))=(0)(1,1)(2,2)(2,1)(3)

ψZ[ω2,ψZ[ω×2](ωω)](ψZ[ω×2](ωω))=(0)(1,1)(2,2)(2,1)(3)(4)

ψZ[ω2](ψZ[ω×2](ωω))=(0)(1,1)(2,2)(2,1)(3,1)

ψZ[ω2](ψZ[ω×2](ωωω))=(0)(1,1)(2,2)(2,1)(3,1)(4,1)

ψZ[ω2](ψZ[ω×2](ψZ(ω)))=(0)(1,1)(2,2)(2,1)(3,2)

ψZ[ω2](ψZ[ω×2](ψZ(ω)+ω))=(0)(1,1)(2,2)(2,1)(3,2)(2,1)

ψZ[ω2](ψZ[ω×2](ψZ(ω+1)))=(0)(1,1)(2,2)(2,1)(3,2)(3)

ψZ[ω2,ψZ[ω×2](ψZ[ω×2](ω×2))](ψZ[ω×2](ψZ[ω×2](ω×2)))=(0)(1,1)(2,2)(2,1)(3,2)(3)(4)

ψZ[ω2](ψZ[ω×2](ψZ[ω×2](ω×2)))=(0)(1,1)(2,2)(2,1)(3,2)(3,1)

ψZ[ω2](ψZ[ω×2](ψZ[ω×2](ω2)))=(0)(1,1)(2,2)(2,1)(3,2)(3,1)(4)

ψZ[ω2](ψZ[ω×2](ψZ[ω×2](ωω)))=(0)(1,1)(2,2)(2,1)(3,2)(3,1)(4,1)

ψZ[ω2](ψZ[ω×2](ψZ[ω×2](ψZ(ω)))=(0)(1,1)(2,2)(2,1)(3,2)(3,1)(4,2)

ψZ[ω2](ψZ(ω×2))=(0)(1,1)(2,2)(2,2)

ψZ[ω2](ψZ[ω2](ω2))=(0)(1,1)(2,2)(3)

ψZ[ω2](ψZ[ω2](ω2+ω))=(0)(1,1)(2,2)(3)(2,2)

ψZ[ω2](ψZ[ω2](ω3))=(0)(1,1)(2,2)(3)(3)

ψZ[ω2,ψZ[ω2,ωω](ωω)](ψZ[ω2,ωω](ωω))=(0)(1,1)(2,2)(3)(4)

ψZ[ω2](ψZ[ω2,ωω](ωω))=(0)(1,1)(2,2)(3,1)

ψZ[ω2](ψZ[ω2,ωω](ωω+1))=(0)(1,1)(2,2)(3,1)(3)

ψZ[ω2](ψZ[ω2,ωω](ωω×2))=(0)(1,1)(2,2)(3,1)(3,1)

ψZ[ω2](ψZ[ω2,ωω](ωω2))=(0)(1,1)(2,2)(3,1)(4)

ψZ[ω2](ψZ[ω2,ωω](ωωω))=(0)(1,1)(2,2)(3,1)(4,1)

ψZ[ω2](ψZ[ω2,ωω](ψZ(ω)))=(0)(1,1)(2,2)(3,1)(4,2)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ω×2)))=(0)(1,1)(2,2)(3,1)(4,2)(3,1)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ω2)))=(0)(1,1)(2,2)(3,1)(4,2)(3,1)(4)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ωω)))=(0)(1,1)(2,2)(3,1)(4,2)(3,1)(4,1)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ψZ(ω))))=(0)(1,1)(2,2)(3,1)(4,2)(3,1)(4,2)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ψZ(ω)+ω)))=(0)(1,1)(2,2)(3,1)(4,2)(3,1)(4,2)(3,1)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ψZ(ω+1))))=(0)(1,1)(2,2)(3,1)(4,2)(4)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ψZ[ω×2](ω×2))))=(0)(1,1)(2,2)(3,1)(4,2)(4,1)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω×2](ψZ[ω×2](ψZ(ω)))))=(0)(1,1)(2,2)(3,1)(4,2)(4,1)(5,2)

ψZ[ω2](ψZ[ω2,ωω](ψZ(ω×2)))=(0)(1,1)(2,2)(3,1)(4,2)(4,2)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω2](ω2)))=(0)(1,1)(2,2)(3,1)(4,2)(5)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω2,ωω](ωω)))=(0)(1,1)(2,2)(3,1)(4,2)(5,1)

ψZ[ω2](ψZ[ω2,ωω](ψZ[ω2,ωω](ψZ(ω))))=(0)(1,1)(2,2)(3,1)(4,2)(5,1)(6,2)

ψZ[ω2](ψZ[ω2](ωω))=(0)(1,1)(2,2)(3,2)

ψZ[ω2](ψZ[ω2](ωω+ω))=(0)(1,1)(2,2)(3,2)(2,2)

ψZ[ω2,ψZ[ω2,ωω×2](ωω×2)](ψZ[ω2,ωω×2](ωω×2))=(0)(1,1)(2,2)(3,2)(2,2)(3)(4)

ψZ[ω2](ψZ[ω2,ωω×2](ωω×2))=(0)(1,1)(2,2)(3,2)(2,2)(3,1)

ψZ[ω2](ψZ[ω2](ωω×2))=(0)(1,1)(2,2)(3,2)(2,2)(3,2)

ψZ[ω2](ψZ[ω2](ωω+1))=(0)(1,1)(2,2)(3,2)(3)

ψZ[ω2,ψZ[ω2,ωω×2](ωω×2)](ψZ[ω2,ωω×2](ωω×2))=(0)(1,1)(2,2)(3,2)(3)(4)

ψZ[ω2](ψZ[ω2,ωω×2](ωω×2))=(0)(1,1)(2,2)(3,2)(3,1)

ψZ[ω2](ψZ[ω2](ωω×2))=(0)(1,1)(2,2)(3,2)(3,2)

ψZ[ω2](ψZ[ω2](ωω2))=(0)(1,1)(2,2)(3,2)(4)

ψZ[ω2](ψZ[ω2](ωωω))=(0)(1,1)(2,2)(3,2)(4,2)

ψZ[ω2](ψZ[ω2](ψZ(ω)))=(0)(1,1)(2,2)(3,3)

ψZ(ω2)=(0)(1,1,1)