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strong fffz分析Part1

来自Googology Wiki
Alice留言 | 贡献2026年7月25日 (六) 15:50的版本 (创建页面,内容为“<math>\psi_Z(0) = 1</math> <math>\psi_Z[1](1) = 2</math> <math>\psi_Z[1](\psi_Z[1](1)) = 3</math> <math>\psi_Z(1) = \omega</math> <math>\psi_Z[2](2) = \omega+1</math> <math>\psi_Z[2](\psi_Z(1)) = \omega \times 2</math> <math>\psi_Z[2](\psi_Z[2](2)) = \omega \times 2+1</math> <math>\psi_Z(2) = \omega^2</math> <math>\psi_Z[\omega](\omega) = \omega^\omega</math> <math>\psi_Z[\omega](\omega+1) = \omega^{\omega+1}</math> <math>\psi_Z[\omega](\omega^2) = \o…”)
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ψZ(0)=1

ψZ[1](1)=2

ψZ[1](ψZ[1](1))=3

ψZ(1)=ω

ψZ[2](2)=ω+1

ψZ[2](ψZ(1))=ω×2

ψZ[2](ψZ[2](2))=ω×2+1

ψZ(2)=ω2

ψZ[ω](ω)=ωω

ψZ[ω](ω+1)=ωω+1

ψZ[ω](ω2)=ωω2

ψZ[ω](ψZ[ω](ω))=ωωω

ψZ(ω)=(0)(1,1)

ψZ(ω+1)=(0)(1,1)(1)

ψZ[ω×2](ω×2)=(0)(1,1)(1)(2)

ψZ[ω×2](ωω)=(0)(1,1)(1)(2)(3)

ψZ[ω×2](ψZ(ω))=(0)(1,1)(1)(2,1)

ψZ[ω×2](ψZ[ω×2](ω×2))=(0)(1,1)(1)(2,1)(2)(3)

ψZ(ω×2)=(0)(1,1)(1,1)

ψZ[ω2](ω2)=(0)(1,1)(2)

ψZ[ω2,ω2+ω](ω2+ω)=(0)(1,1)(2)(1)(2)

ψZ[ω2](ω2+ω)=(0)(1,1)(2)(1,1)

ψZ[ω2](ω2×2)=(0)(1,1)(2)(1,1)(2)

ψZ[ω2](ω3)=(0)(1,1)(2)(2)

ψZ[ω2,ωω](ωω)=(0)(1,1)(2)(3)

ψZ[ω2,ωω](ψZ(ω))=(0)(1,1)(2)(3,1)

ψZ[ω2,ωω](ψZ[ω2,ωω](ωω))=(0)(1,1)(2)(3,1)(4)(5)

ψZ[ω2](ωω)=(0)(1,1)(2,1)

ψZ[ω2](ωω+ω)=(0)(1,1)(2,1)(1,1)

ψZ[ω2,ωω×2](ωω×2)=(0)(1,1)(2,1)(1,1)(2)(3)

ψZ[ω2](ωω×2)=(0)(1,1)(2,1)(1,1)(2,1)

ψZ[ω2](ωω+1)=(0)(1,1)(2,1)(2)

ψZ[ω2](ωω+1+ωω)=(0)(1,1)(2,1)(2)(1,1)(2,1)

ψZ[ω2](ωω+2)=(0)(1,1)(2,1)(2)(2)

ψZ[ω2,ωω×2](ωω×2)=(0)(1,1)(2,1)(2)(3)

ψZ[ω2,ωω×2](ψZ(ω))=(0)(1,1)(2,1)(2)(3,1)

ψZ[ω2,ωω×2](ψZ[ω2,ωω×2](ωω×2))=(0)(1,1)(2,1)(2)(3,1)(4,1)(4)(5)

ψZ[ω2](ωω×2)=(0)(1,1)(2,1)(2,1)

ψZ[ω2](ωω2)=(0)(1,1)(2,1)(3)

ψZ[ω2](ωω2+ω)=(0)(1,1)(2,1)(3)(2,1)

ψZ[ω2](ωω3)=(0)(1,1)(2,1)(3)(3)

ψZ[ω2,ωωω](ωωω)=(0)(1,1)(2,1)(3)(4)

ψZ[ω2,ωωω](ψZ(ω))=(0)(1,1)(2,1)(3)(4,1)

ψZ[ω2,ωωω](ψZ[ω2,ωωω](ωωω))=(0)(1,1)(2,1)(3)(4,1)(5,1)(6)(7)

ψZ[ω2](ωωω)=(0)(1,1)(2,1)(3,1)

ψZ[ω2](ωωω+ω)=(0)(1,1)(2,1)(3,1)(2,1)

ψZ[ω2](ωωω+1)=(0)(1,1)(2,1)(3,1)(3)

ψZ[ω2](ωωω×2)=(0)(1,1)(2,1)(3,1)(3,1)

ψZ[ω2](ωωω2)=(0)(1,1)(2,1)(3,1)(4)

ψZ[ω2,ωωωω](ωωωω)=(0)(1,1)(2,1)(3,1)(4)(5)

ψZ[ω2](ωωωω)=(0)(1,1)(2,1)(3,1)(4,1)

ψZ[ω2](ψZ(ω))=(0)(1,1)(2,2)