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strong fffz分析Part2

来自Googology Wiki
Alice留言 | 贡献2026年7月25日 (六) 17:18的版本 (创建页面,内容为“<math>\psi_Z(\omega^2) = (0)(1,1,1)</math> <math>\psi_Z(\omega^2+\omega) = (0)(1,1,1)(1,1)</math> <math>\psi_Z[\omega^2 \times 2](\omega^2 \times 2) = (0)(1,1,1)(1,1)(2)</math> <math>\psi_Z[\omega^2 \times 2, \omega^\omega](\omega^\omega) = (0)(1,1,1)(1,1)(2)(3)</math> <math>\psi_Z[\omega^2 \times 2](\omega^\omega) = (0)(1,1,1)(1,1)(2,1)</math> <math>\psi_Z[\omega^2 \times 2](\omega^{\omega^\omega}) = (0)(1,1,1)(1,1)(2,1)(3,1)</math> <math>\psi_Z[\omega^2…”)
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ψZ(ω2)=(0)(1,1,1)

ψZ(ω2+ω)=(0)(1,1,1)(1,1)

ψZ[ω2×2](ω2×2)=(0)(1,1,1)(1,1)(2)

ψZ[ω2×2,ωω](ωω)=(0)(1,1,1)(1,1)(2)(3)

ψZ[ω2×2](ωω)=(0)(1,1,1)(1,1)(2,1)

ψZ[ω2×2](ωωω)=(0)(1,1,1)(1,1)(2,1)(3,1)

ψZ[ω2×2](ψZ(ω))=(0)(1,1,1)(1,1)(2,2)

ψZ[ω2×2](ψZ(ω2))=(0)(1,1,1)(1,1)(2,2,1)

ψZ[ω2×2](ψZ(ω2)+ω)=(0)(1,1,1)(1,1)(2,2,1)(1,1)

ψZ[ω2×2](ψZ(ω2)×2)=(0)(1,1,1)(1,1)(2,2,1)(1,1)(2,2,1)

ψZ[ω2×2](ψZ(ω2+1))=(0)(1,1,1)(1,1)(2,2,1)(2)

ψZ[ω2×2,ψZ[ω2+ω](ω2+ω)](ψZ[ω2+ω](ω2+ω))=(0)(1,1,1)(1,1)(2,2,1)(2)(3)

ψZ[ω2×2](ψZ[ω2+ω](ω2+ω))=(0)(1,1,1)(1,1)(2,2,1)(2,1)

ψZ[ω2×2](ψZ[ω2+ω](ωω))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,1)

ψZ[ω2×2](ψZ[ω2+ω](ψZ(ω)))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,2)

ψZ[ω2×2](ψZ[ω2+ω](ψZ(ω2)))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,2,1)

ψZ[ω2×2](ψZ[ω2+ω](ψZ(ω2)+1))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,2,1)(2,1)

ψZ[ω2×2](ψZ[ω2+ω](ψZ(ω2)×2))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,2,1)(2,1)(3,2,1)

ψZ[ω2×2](ψZ[ω2+ω](ψZ(ω2+1)))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,2,1)(3)

ψZ[ω2×2](ψZ[ω2+ω](ψZ[ω2+ω](ω2+ω)))=(0)(1,1,1)(1,1)(2,2,1)(2,1)(3,2,1)(3,1)

ψZ[ω2×2](ψZ(ω2+ω))=(0)(1,1,1)(1,1)(2,2,1)(2,2)

ψZ[ω2×2](ψZ(ω2+ω+1))=(0)(1,1,1)(1,1)(2,2,1)(2,2)(2)