strong fffz分析Part2：修订间差异

2026年7月25日 (六) 17:23的版本

$ψ_{Z} (ω^{2}) = (0) (1, 1, 1)$

$ψ_{Z} (ω^{2} + ω) = (0) (1, 1, 1) (1, 1)$

$ψ_{Z} [ω^{2} \times 2] (ω^{2} \times 2) = (0) (1, 1, 1) (1, 1) (2)$

$ψ_{Z} [ω^{2} \times 2, ω^{ω}] (ω^{ω}) = (0) (1, 1, 1) (1, 1) (2) (3)$

$ψ_{Z} [ω^{2} \times 2] (ω^{ω}) = (0) (1, 1, 1) (1, 1) (2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ω^{ω^{ω}}) = (0) (1, 1, 1) (1, 1) (2, 1) (3, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω)) = (0) (1, 1, 1) (1, 1) (2, 2)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2})) = (0) (1, 1, 1) (1, 1) (2, 2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2}) + ω) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (1, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2}) \times 2) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (1, 1) (2, 2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2} + 1)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2)$

$ψ_{Z} [ω^{2} \times 2, ψ_{Z} [ω^{2} + ω] (ω^{2} + ω)] (ψ_{Z} [ω^{2} + ω] (ω^{2} + ω)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2) (3)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ω^{2} + ω)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ω^{ω})) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ψ_{Z} (ω))) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 2)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ψ_{Z} (ω^{2}))) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ψ_{Z} (ω^{2}) + 1)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 2, 1) (2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ψ_{Z} (ω^{2}) \times 2)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 2, 1) (2, 1) (3, 2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ψ_{Z} (ω^{2} + 1))) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 2, 1) (3)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω] (ψ_{Z} [ω^{2} + ω] (ω^{2} + ω))) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 1) (3, 2, 1) (3, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2} + ω)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2} + ω + 1)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (2)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} + ω \times 2] (ω^{2} + ω \times 2)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (2, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2} + ω \times 2)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (2, 2)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} \times 2] (ω^{2} \times 2)) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (3)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} \times 2, ω^{ω}] (ω^{ω})) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (3, 1)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} \times 2] (ω^{ω})) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (3, 2)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω))) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (3, 3)$

$ψ_{Z} [ω^{2} \times 2] (ψ_{Z} [ω^{2} \times 2] (ψ_{Z} (ω^{2}))) = (0) (1, 1, 1) (1, 1) (2, 2, 1) (2, 2) (3, 3, 1)$

$ψ_{Z} (ω^{2} \times 2) = (0) (1, 1, 1) (1, 1, 1)$

$ψ_{Z} [ω^{3}] (ω^{3}) = (0) (1, 1, 1) (2)$

$ψ_{Z} [ω^{3}, ω^{ω}] (ω^{ω}) = (0) (1, 1, 1) (2, 1)$

@@ 第42行： / 第42行： @@
 <math>\psi_Z[\omega^2 \times 2](\psi_Z(\omega^2+\omega+1)) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(2)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z[\omega^2+\omega \times 2](\omega^2+\omega \times 2)) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(2,1)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z(\omega^2+\omega \times 2)) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(2,2)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z[\omega^2 \times 2](\omega^2 \times 2)) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(3)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z[\omega^2 \times 2, \omega^\omega](\omega^\omega)) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(3,1)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z[\omega^2 \times 2](\omega^\omega)) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(3,2)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z[\omega^2 \times 2](\psi_Z(\omega))) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(3,3)</math>
+<math>\psi_Z[\omega^2 \times 2](\psi_Z[\omega^2 \times 2](\psi_Z(\omega^2))) = (0)(1,1,1)(1,1)(2,2,1)(2,2)(3,3,1)</math>
+<math>\psi_Z(\omega^2 \times 2) = (0)(1,1,1)(1,1,1)</math>
+<math>\psi_Z[\omega^3](\omega^3) = (0)(1,1,1)(2)</math>
+<math>\psi_Z[\omega^3, \omega^\omega](\omega^\omega) = (0)(1,1,1)(2,1)</math>