Y 序列 vs TBMS：修订间差异

2025年8月26日 (二) 10:44的版本

本条目展示Y序列和 $T B M S$ 的强度对照。这些分析出自梅天狸

序数行BMS规则：使用 $n^{α}$ 表示连续的 $α$ 行n.位于后继序数行的项的父项、祖先项定义同BMS;位于极限序数行的项的父项列标为同一列、行数小于它的项父项列标的下确界.LNZ（末列最后一个非零项，Last non zero）位于后继序数行时，展开同BMS；LNZ位于极限序数行时，不展开，取末列行标的基本列。

Part 1

$(0) (1^{ω}) = Y (1, 3)$
$(0) (1^{ω}) (0) (1^{ω}) = Y (1, 3, 1, 3)$
$(0) (1^{ω}) (1) = Y (1, 3, 2)$
$(0) (1^{ω}) (1) (2) = Y (1, 3, 2, 3)$
$(0) (1^{ω}) (1) (2, 1) = Y (1, 3, 2, 4)$
$(0) (1^{ω}) (1) (2, 1) (3, 1) = Y (1, 3, 2, 4, 6)$
$(0) (1^{ω}) (1) (2, 1) (3, 2) = Y (1, 3, 2, 4, 7)$
$(0) (1^{ω}) (1) (2, 1, 1) = Y (1, 3, 2, 4, 8)$
$(0) (1^{ω}) (1) (2, 1, 1, 1) = Y (1, 3, 2, 4, 8, 16)$
$(0) (1^{ω}) (1) (2, 1^{ω}) = Y (1, 3, 2, 5)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (1) = Y (1, 3, 2, 5, 2)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (1) (2, 1^{ω}) = Y (1, 3, 2, 5, 2, 5)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (2) = Y (1, 3, 2, 5, 3)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (2) (3, 1) = Y (1, 3, 2, 5, 3, 5)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (2) (3, 1, 1) = Y (1, 3, 2, 5, 3, 5, 9)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (2) (3, 1^{ω}) = Y (1, 3, 2, 5, 3, 6)$
$(0) (1^{ω}) (1) (2, 1^{ω}) (2) (3, 1^{ω}) (3) (4, 1^{ω}) = Y (1, 3, 2, 5, 3, 6, 4, 7)$
$(0) (1^{ω}) (1, 1) = Y (1, 3, 2, 5, 4)$
$(0) (1^{ω}) (1, 1) (2) = Y (1, 3, 2, 5, 4, 5)$
$(0) (1^{ω}) (1, 1) (2, 1) = Y (1, 3, 2, 5, 4, 6)$
$(0) (1^{ω}) (1, 1) (2, 2) = Y (1, 3, 2, 5, 4, 7)$
$(0) (1^{ω}) (1, 1) (2, 2, 1) = Y (1, 3, 2, 5, 4, 8)$
$(0) (1^{ω}) (1, 1) (2, 2, 1, 1) = Y (1, 3, 2, 5, 4, 8, 16)$
$(0) (1^{ω}) (1, 1) (2, 2, 1^{ω}) = Y (1, 3, 2, 5, 4, 9)$
$(0) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (2, 2) = Y (1, 3, 2, 5, 4, 9, 7)$
$(0) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (2, 2) (3, 3) = Y (1, 3, 2, 5, 4, 9, 7, 11)$
$(0) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (2, 2) (3, 3, 1) = Y (1, 3, 2, 5, 4, 9, 7, 12)$
$(0) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (2, 2) (3, 3, 1, 1) = Y (1, 3, 2, 5, 4, 9, 7, 12, 21)$
$(0) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (2, 2) (3, 3, 1^{ω}) = Y (1, 3, 2, 5, 4, 9, 7, 13)$
$(0) (1^{ω}) (1, 1, 1) = Y (1, 3, 2, 5, 4, 9, 8)$
$(0) (1^{ω}) (1, 1, 1) (2, 2, 2) = Y (1, 3, 2, 5, 4, 9, 8, 15)$
$(0) (1^{ω}) (1, 1, 1) (2, 2, 2, 1) = Y (1, 3, 2, 5, 4, 9, 8, 16)$
$(0) (1^{ω}) (1, 1, 1) (2, 2, 2, 1^{ω}) = Y (1, 3, 2, 5, 4, 9, 8, 17)$
$(0) (1^{ω}) (1, 1, 1, 1) = Y (1, 3, 2, 5, 4, 9, 8, 17, 16)$
$(0) (1^{ω}) (1^{ω}) = Y (1, 3, 3)$
$(0) (1^{ω}) (1^{ω}) (1^{ω}) = Y (1, 3, 3, 3)$
$(0) (1^{ω}) (2) = Y (1, 3, 4)$

Part 2

$(0) (1^{ω}) (2) (1) = Y (1, 3, 4, 2)$
$(0) (1^{ω}) (2) (1) (2, 1) = Y (1, 3, 4, 2, 4)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) = Y (1, 3, 4, 2, 5)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (2) = Y (1, 3, 4, 2, 5, 3)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (2) (3, 1^{ω}) = Y (1, 3, 4, 2, 5, 3, 6)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (2, 1) = Y (1, 3, 4, 2, 5, 4)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (2, 1) (3, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 4, 9)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (2, 1, 1) = Y (1, 3, 4, 2, 5, 4, 9, 8)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (2, 1^{ω}) = Y (1, 3, 4, 2, 5, 5)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (3) = Y (1, 3, 4, 2, 5, 6)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (3) (2) = Y (1, 3, 4, 2, 5, 6, 3)$
$(0) (1^{ω}) (2) (1) (2, 1^{ω}) (3) (2) (3, 1^{ω}) (4) = Y (1, 3, 4, 2, 5, 6, 3, 6, 7)$
$(0) (1^{ω}) (2) (1, 1) = Y (1, 3, 4, 2, 5, 6, 4)$
$(0) (1^{ω}) (2) (1, 1) (2, 2) = Y (1, 3, 4, 2, 5, 6, 4, 7)$
$(0) (1^{ω}) (2) (1, 1) (2, 2, 1) = Y (1, 3, 4, 2, 5, 6, 4, 8)$
$(0) (1^{ω}) (2) (1, 1) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 6, 4, 9)$
$(0) (1^{ω}) (2) (1, 1) (2, 2, 1^{ω}) (3) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10)$
$(0) (1^{ω}) (2) (1, 1) (2, 2, 1^{ω}) (3) (2, 2) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 7)$
$(0) (1^{ω}) (2) (1, 1) (2, 2, 1^{ω}) (3) (2, 2) (3, 3, 1^{ω}) (4) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 7, 13, 14)$
$(0) (1^{ω}) (2) (1, 1, 1) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 8)$
$(0) (1^{ω}) (2) (1, 1, 1) (2, 2, 2, 1) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 8, 16)$
$(0) (1^{ω}) (2) (1, 1, 1) (2, 2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 8, 17)$
$(0) (1^{ω}) (2) (1, 1, 1) (2, 2, 2, 1^{ω}) (3) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 8, 17, 18)$
$(0) (1^{ω}) (2) (1, 1, 1) (2, 2, 2, 1^{ω}) (3) (2, 2, 2) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 8, 17, 18, 15)$
$(0) (1^{ω}) (2) (1, 1, 1, 1) = Y (1, 3, 4, 2, 5, 6, 4, 9, 10, 8, 17, 18, 16)$
$(0) (1^{ω}) (2) (1^{ω}) = Y (1, 3, 4, 2, 5, 6, 5)$
$(0) (1^{ω}) (2) (1^{ω}) (2) = Y (1, 3, 4, 2, 5, 6, 5, 6)$
$(0) (1^{ω}) (2) (2) = Y (1, 3, 4, 2, 5, 6, 6)$
$(0) (1^{ω}) (2) (3, 1) = Y (1, 3, 4, 2, 5, 6, 8)$
$(0) (1^{ω}) (2) (3, 1, 1) = Y (1, 3, 4, 2, 5, 6, 8, 12)$
$(0) (1^{ω}) (2) (3, 1^{ω}) = Y (1, 3, 4, 2, 5, 6, 9)$
$(0) (1^{ω}) (2) (3, 1^{ω}) (4) = Y (1, 3, 4, 2, 5, 6, 9, 10)$
$(0) (1^{ω}) (2) (3, 1^{ω}) (4) (5, 1^{ω}) = Y (1, 3, 4, 2, 5, 6, 9, 10, 13)$
$(0) (1^{ω}) (2, 1) = Y (1, 3, 4, 2, 5, 7)$

Part 3

$(0) (1^{ω}) (2, 1) (1) = Y (1, 3, 4, 2, 5, 7, 2)$
$(0) (1^{ω}) (2, 1) (1) (2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 2, 5)$
$(0) (1^{ω}) (2, 1) (1) (2, 1^{ω}) (3) = Y (1, 3, 4, 2, 5, 7, 2, 5, 6)$
$(0) (1^{ω}) (2, 1) (1) (2, 1^{ω}) (3) (2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 2, 5, 6, 5)$
$(0) (1^{ω}) (2, 1) (1) (2, 1^{ω}) (3, 1) = Y (1, 3, 4, 2, 5, 7, 2, 5, 7)$
$(0) (1^{ω}) (2, 1) (1) (2, 1^{ω}) (3, 1) (2) = Y (1, 3, 4, 2, 5, 7, 3)$
$(0) (1^{ω}) (2, 1) (1) (2, 1^{ω}) (3, 1) (2) (3, 1^{ω}) (4, 1) = Y (1, 3, 4, 2, 5, 7, 3, 6, 8)$
$(0) (1^{ω}) (2, 1) (1, 1) = Y (1, 3, 4, 2, 5, 7, 4)$
$(0) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9)$
$(0) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12)$
$(0) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 7)$
$(0) (1^{ω}) (2, 1) (1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 8)$
$(0) (1^{ω}) (2, 1) (1, 1, 1) (2, 2, 2, 1^{ω}) (3, 2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 8, 17, 22)$
$(0) (1^{ω}) (2, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 4)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1, 1) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 4, 9)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 4, 9, 12, 9)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 5)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 7)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 8)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 9)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 4)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 4, 9)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 4, 9, 12, 9, 11)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 5)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 7)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 9)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (2, 2, 1^{ω}) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 9, 11)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 11)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (4, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 16)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 1) (4, 2, 1^{ω}) (5, 2) (4, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 11, 16, 19, 16)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 12)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) (2, 2, 1^{ω}) (3, 2) (2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 12, 7)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 12, 8)$
$(0) (1^{ω}) (2, 1) (1^{ω}) (2, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 9, 12, 9)$
$(0) (1^{ω}) (2, 1) (2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10)$
$(0) (1^{ω}) (2, 1) (2) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 12)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15, 12)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) (3, 1) (4, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15, 12, 17)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) (3, 1) (4, 2, 1^{ω}) (5, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15, 12, 17, 20)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) (3, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15, 12, 17, 20, 17)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) (3, 1^{ω}) (4, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15, 12, 17, 20, 17, 19)$
$(0) (1^{ω}) (2, 1) (2) (3, 1^{ω}) (4, 1) (4) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 10, 13, 15, 12, 17, 20, 17, 19, 18)$
$(0) (1^{ω}) (2, 1) (2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 11)$
$(0) (1^{ω}) (2, 1) (2, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 12, 9)$
$(0) (1^{ω}) (2, 1) (2, 1) (2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 12, 11)$
$(0) (1^{ω}) (2, 1) (3) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 13)$
$(0) (1^{ω}) (2, 1) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 14)$
$(0) (1^{ω}) (2, 1) (3, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 15, 9)$
$(0) (1^{ω}) (2, 1) (3, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 16)$
$(0) (1^{ω}) (2, 1) (3, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 18)$
$(0) (1^{ω}) (2, 1) (3, 2, 1^{ω}) (4, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 18, 20)$
$(0) (1^{ω}) (2, 1) (3, 2, 1^{ω}) (4, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 18, 21, 9)$
$(0) (1^{ω}) (2, 1) (3, 2, 1^{ω}) (4, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 18, 22)$
$(0) (1^{ω}) (2, 1) (3, 2, 1^{ω}) (4, 2) (5, 3, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 12, 18, 22, 29)$
$(0) (1^{ω}) (2, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13)$
$(0) (1^{ω}) (2, 1, 1) (1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) (2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) (2, 1) (3, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4, 9)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) (2, 1) (3, 2, 1^{ω}) (4, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4, 9, 12)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) (2, 1) (3, 2, 1^{ω}) (4, 2) (3, 2) (4, 3, 1^{ω}) (5, 3) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4, 9, 12, 7, 13, 17)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) (2, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4, 9, 12, 8)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1) (2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4, 9, 12, 9)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 2, 5, 7, 4, 9, 13)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1, 1) (2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 3)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1, 1) (2) (3, 1^{ω}) (4, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 3, 6, 8)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1, 1) (2) (3, 1^{ω}) (4, 1) (3, 1) (4, 2, 1^{ω}) (5, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 3, 6, 8, 5, 10, 13)$
$(0) (1^{ω}) (2, 1, 1) (1) (2, 1^{ω}) (3, 1, 1) (2) (3, 1^{ω}) (4, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 3, 6, 8, 5, 10, 14)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 4)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) (2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 4, 9)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) (2, 2, 1^{ω}) (3, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 4, 9, 12)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) (2, 2, 1^{ω}) (3, 2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 4, 9, 13)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) (2, 2, 1^{ω}) (3, 2, 1) (2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 5)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) (2, 2, 1^{ω}) (3, 2, 1) (2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 7)$
$(0) (1^{ω}) (2, 1, 1) (1, 1) (2, 2, 1^{ω}) (3, 2, 1) (2, 2) (3, 3, 1^{ω}) (4, 3, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 7, 13, 18)$
$(0) (1^{ω}) (2, 1, 1) (1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8)$
$(0) (1^{ω}) (2, 1, 1) (1, 1, 1) (2, 2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17)$
$(0) (1^{ω}) (2, 1, 1) (1, 1, 1) (2, 2, 2, 1^{ω}) (3, 2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24)$
$(0) (1^{ω}) (2, 1, 1) (1, 1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 16)$
$(0) (1^{ω}) (2, 1, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 17)$
$(0) (1^{ω}) (2, 1, 1) (1^{ω}) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 17, 17)$
$(0) (1^{ω}) (2, 1, 1) (1^{ω}) (2, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 17, 19)$
$(0) (1^{ω}) (2, 1, 1) (1^{ω}) (2, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 17, 20, 17)$
$(0) (1^{ω}) (2, 1, 1) (1^{ω}) (2, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 17, 21)$
$(0) (1^{ω}) (2, 1, 1) (1^{ω}) (2, 1, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 17, 24, 17)$
$(0) (1^{ω}) (2, 1, 1) (2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 18)$
$(0) (1^{ω}) (2, 1, 1) (2, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 20, 17)$
$(0) (1^{ω}) (2, 1, 1) (2, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 21)$
$(0) (1^{ω}) (2, 1, 1) (2, 1, 1) (1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 24, 17)$
$(0) (1^{ω}) (2, 1, 1) (3, 2, 2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 37)$
$(0) (1^{ω}) (2, 1, 1) (3, 2, 2, 1^{ω}) (4, 2, 2) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 24, 37, 48)$
$(0) (1^{ω}) (2, 1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 25)$
$(0) (1^{ω}) (2, 1, 1, 1, 1) = Y (1, 3, 4, 2, 5, 7, 4, 9, 13, 8, 17, 25, 16, 33, 49)$
$(0) (1^{ω}) (2, 1^{ω}) = Y (1, 3, 4, 2, 5, 7, 5)$

后续分析参见Y序列 VS TBMS Part2、Y序列 VS TBMS Part3

@@ 第3行： / 第3行： @@
 序数行BMS规则：使用<math>n^\alpha</math>表示连续的<math>\alpha</math>行n.位于后继序数行的项的父项、祖先项定义同[[Bashicu矩阵|BMS]];位于极限序数行的项的父项列标为同一列、行数小于它的项父项列标的下确界.LNZ（末列最后一个非零项，Last non zero）位于后继序数行时，展开同BMS；LNZ位于极限序数行时，不展开，取末列行标的基本列。
-\begin{align}s\\&(0)(1^\omega)=Y(1,3)\\&(0)(1^\omega)(0)(1^\omega)=Y(1,3,1,3)\\&(0)(1^\omega)(1)=Y(1,3,2)\\&(0)(1^\omega)(1)(2)=Y(1,3,2,3)\\&(0)(1^\omega)(1)(2,1)=Y(1,3,2,4)\\&(0)(1^\omega)(1)(2,1)(3,1)=Y(1,3,2,4,6)\\&(0)(1^\omega)(1)(2,1)(3,2)=Y(1,3,2,4,7)\\&(0)(1^\omega)(1)(2,1,1)=Y(1,3,2,4,8)\\&(0)(1^\omega)(1)(2,1,1,1)=Y(1,3,2,4,8,16)\\&(0)(1^\omega)(1)(2,1^\omega)=Y(1,3,2,5)\\&(0)(1^\omega)(1)(2,1^\omega)(1)=Y(1,3,2,5,2)\\&(0)(1^\omega)(1)(2,1^\omega)(1)(2,1^\omega)=Y(1,3,2,5,2,5)\\&(0)(1^\omega)(1)(2,1^\omega)(2)=Y(1,3,2,5,3)\\&(0)(1^\omega)(1)(2,1^\omega)(2)(3,1)=Y(1,3,2,5,3,5)\\&(0)(1^\omega)(1)(2,1^\omega)(2)(3,1,1)=Y(1,3,2,5,3,5,9)\\&(0)(1^\omega)(1)(2,1^\omega)(2)(3,1^\omega)=Y(1,3,2,5,3,6)\\&(0)(1^\omega)(1)(2,1^\omega)(2)(3,1^\omega)(3)(4,1^\omega)=Y(1,3,2,5,3,6,4,7)\\&(0)(1^\omega)(1,1)=Y(1,3,2,5,4)\\&(0)(1^\omega)(1,1)(2)=Y(1,3,2,5,4,5)\\&(0)(1^\omega)(1,1)(2,1)=Y(1,3,2,5,4,6)\\&(0)(1^\omega)(1,1)(2,2)=Y(1,3,2,5,4,7)\\&(0)(1^\omega)(1,1)(2,2,1)=Y(1,3,2,5,4,8)\\&(0)(1^\omega)(1,1)(2,2,1,1)=Y(1,3,2,5,4,8,16)\\&(0)(1^\omega)(1,1)(2,2,1^\omega)=Y(1,3,2,5,4,9)\\&(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)=Y(1,3,2,5,4,9,7)\\&(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3)=Y(1,3,2,5,4,9,7,11)\\&(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3,1)=Y(1,3,2,5,4,9,7,12)\\&(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3,1,1)=Y(1,3,2,5,4,9,7,12,21)\\&(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3,1^\omega)=Y(1,3,2,5,4,9,7,13)\\&(0)(1^\omega)(1,1,1)=Y(1,3,2,5,4,9,8)\\&(0)(1^\omega)(1,1,1)(2,2,2)=Y(1,3,2,5,4,9,8,15)\\&(0)(1^\omega)(1,1,1)(2,2,2,1)=Y(1,3,2,5,4,9,8,16)\\&(0)(1^\omega)(1,1,1)(2,2,2,1^\omega)=Y(1,3,2,5,4,9,8,17)\\&(0)(1^\omega)(1,1,1,1)=Y(1,3,2,5,4,9,8,17,16)\\&(0)(1^\omega)(1^\omega)=Y(1,3,3)\\&(0)(1^\omega)(1^\omega)(1^\omega)=Y(1,3,3,3)\\&(0)(1^\omega)(2)=Y(1,3,4)\end{align}
+=== Part 1 ===
+* <math>(0)(1^\omega)=Y(1,3)</math>
+* <math>(0)(1^\omega)(0)(1^\omega)=Y(1,3,1,3)</math>
+* <math>(0)(1^\omega)(1)=Y(1,3,2)</math>
+* <math>(0)(1^\omega)(1)(2)=Y(1,3,2,3)</math>
+* <math>(0)(1^\omega)(1)(2,1)=Y(1,3,2,4)</math>
+* <math>(0)(1^\omega)(1)(2,1)(3,1)=Y(1,3,2,4,6)</math>
+* <math>(0)(1^\omega)(1)(2,1)(3,2)=Y(1,3,2,4,7)</math>
+* <math>(0)(1^\omega)(1)(2,1,1)=Y(1,3,2,4,8)</math>
+* <math>(0)(1^\omega)(1)(2,1,1,1)=Y(1,3,2,4,8,16)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)=Y(1,3,2,5)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(1)=Y(1,3,2,5,2)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(1)(2,1^\omega)=Y(1,3,2,5,2,5)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(2)=Y(1,3,2,5,3)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(2)(3,1)=Y(1,3,2,5,3,5)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(2)(3,1,1)=Y(1,3,2,5,3,5,9)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(2)(3,1^\omega)=Y(1,3,2,5,3,6)</math>
+* <math>(0)(1^\omega)(1)(2,1^\omega)(2)(3,1^\omega)(3)(4,1^\omega)=Y(1,3,2,5,3,6,4,7)</math>
+* <math>(0)(1^\omega)(1,1)=Y(1,3,2,5,4)</math>
+* <math>(0)(1^\omega)(1,1)(2)=Y(1,3,2,5,4,5)</math>
+* <math>(0)(1^\omega)(1,1)(2,1)=Y(1,3,2,5,4,6)</math>
+* <math>(0)(1^\omega)(1,1)(2,2)=Y(1,3,2,5,4,7)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1)=Y(1,3,2,5,4,8)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1,1)=Y(1,3,2,5,4,8,16)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1^\omega)=Y(1,3,2,5,4,9)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)=Y(1,3,2,5,4,9,7)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3)=Y(1,3,2,5,4,9,7,11)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3,1)=Y(1,3,2,5,4,9,7,12)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3,1,1)=Y(1,3,2,5,4,9,7,12,21)</math>
+* <math>(0)(1^\omega)(1,1)(2,2,1^\omega)(2,2)(3,3,1^\omega)=Y(1,3,2,5,4,9,7,13)</math>
+* <math>(0)(1^\omega)(1,1,1)=Y(1,3,2,5,4,9,8)</math>
+* <math>(0)(1^\omega)(1,1,1)(2,2,2)=Y(1,3,2,5,4,9,8,15)</math>
+* <math>(0)(1^\omega)(1,1,1)(2,2,2,1)=Y(1,3,2,5,4,9,8,16)</math>
+* <math>(0)(1^\omega)(1,1,1)(2,2,2,1^\omega)=Y(1,3,2,5,4,9,8,17)</math>
+* <math>(0)(1^\omega)(1,1,1,1)=Y(1,3,2,5,4,9,8,17,16)</math>
+* <math>(0)(1^\omega)(1^\omega)=Y(1,3,3)</math>
+* <math>(0)(1^\omega)(1^\omega)(1^\omega)=Y(1,3,3,3)</math>
+* <math>(0)(1^\omega)(2)=Y(1,3,4)</math>
-\begin{align}s\\&(0)(1^\omega)(2)(1)=Y(1,3,4,2)\\&(0)(1^\omega)(2)(1)(2,1)=Y(1,3,4,2,4)\\&(0)(1^\omega)(2)(1)(2,1^\omega)=Y(1,3,4,2,5)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(2)=Y(1,3,4,2,5,3)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(2)(3,1^\omega)=Y(1,3,4,2,5,3,6)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(2,1)=Y(1,3,4,2,5,4)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(2,1)(3,2,1^\omega)=Y(1,3,4,2,5,4,9)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(2,1,1)=Y(1,3,4,2,5,4,9,8)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(2,1^\omega)=Y(1,3,4,2,5,5)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(3)=Y(1,3,4,2,5,6)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(3)(2)=Y(1,3,4,2,5,6,3)\\&(0)(1^\omega)(2)(1)(2,1^\omega)(3)(2)(3,1^\omega)(4)=Y(1,3,4,2,5,6,3,6,7)\\&(0)(1^\omega)(2)(1,1)=Y(1,3,4,2,5,6,4)\\&(0)(1^\omega)(2)(1,1)(2,2)=Y(1,3,4,2,5,6,4,7)\\&(0)(1^\omega)(2)(1,1)(2,2,1)=Y(1,3,4,2,5,6,4,8)\\&(0)(1^\omega)(2)(1,1)(2,2,1^\omega)=Y(1,3,4,2,5,6,4,9)\\&(0)(1^\omega)(2)(1,1)(2,2,1^\omega)(3)=Y(1,3,4,2,5,6,4,9,10)\\&(0)(1^\omega)(2)(1,1)(2,2,1^\omega)(3)(2,2)=Y(1,3,4,2,5,6,4,9,10,7)\\&(0)(1^\omega)(2)(1,1)(2,2,1^\omega)(3)(2,2)(3,3,1^\omega)(4)=Y(1,3,4,2,5,6,4,9,10,7,13,14)\\&(0)(1^\omega)(2)(1,1,1)=Y(1,3,4,2,5,6,4,9,10,8)\\&(0)(1^\omega)(2)(1,1,1)(2,2,2,1)=Y(1,3,4,2,5,6,4,9,10,8,16)\\&(0)(1^\omega)(2)(1,1,1)(2,2,2,1^\omega)=Y(1,3,4,2,5,6,4,9,10,8,17)\\&(0)(1^\omega)(2)(1,1,1)(2,2,2,1^\omega)(3)=Y(1,3,4,2,5,6,4,9,10,8,17,18)\\&(0)(1^\omega)(2)(1,1,1)(2,2,2,1^\omega)(3)(2,2,2)=Y(1,3,4,2,5,6,4,9,10,8,17,18,15)\\&(0)(1^\omega)(2)(1,1,1,1)=Y(1,3,4,2,5,6,4,9,10,8,17,18,16)\\&(0)(1^\omega)(2)(1^\omega)=Y(1,3,4,2,5,6,5)\\&(0)(1^\omega)(2)(1^\omega)(2)=Y(1,3,4,2,5,6,5,6)\\&(0)(1^\omega)(2)(2)=Y(1,3,4,2,5,6,6)\\&(0)(1^\omega)(2)(3,1)=Y(1,3,4,2,5,6,8)\\&(0)(1^\omega)(2)(3,1,1)=Y(1,3,4,2,5,6,8,12)\\&(0)(1^\omega)(2)(3,1^\omega)=Y(1,3,4,2,5,6,9)\\&(0)(1^\omega)(2)(3,1^\omega)(4)=Y(1,3,4,2,5,6,9,10)\\&(0)(1^\omega)(2)(3,1^\omega)(4)(5,1^\omega)=Y(1,3,4,2,5,6,9,10,13)\\&(0)(1^\omega)(2,1)=Y(1,3,4,2,5,7)\end{align}
+=== Part 2 ===
+* <math>(0)(1^\omega)(2)(1)=Y(1,3,4,2)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1)=Y(1,3,4,2,4)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)=Y(1,3,4,2,5)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(2)=Y(1,3,4,2,5,3)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(2)(3,1^\omega)=Y(1,3,4,2,5,3,6)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(2,1)=Y(1,3,4,2,5,4)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(2,1)(3,2,1^\omega)=Y(1,3,4,2,5,4,9)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(2,1,1)=Y(1,3,4,2,5,4,9,8)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(2,1^\omega)=Y(1,3,4,2,5,5)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(3)=Y(1,3,4,2,5,6)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(3)(2)=Y(1,3,4,2,5,6,3)</math>
+* <math>(0)(1^\omega)(2)(1)(2,1^\omega)(3)(2)(3,1^\omega)(4)=Y(1,3,4,2,5,6,3,6,7)</math>
+* <math>(0)(1^\omega)(2)(1,1)=Y(1,3,4,2,5,6,4)</math>
+* <math>(0)(1^\omega)(2)(1,1)(2,2)=Y(1,3,4,2,5,6,4,7)</math>
+* <math>(0)(1^\omega)(2)(1,1)(2,2,1)=Y(1,3,4,2,5,6,4,8)</math>
+* <math>(0)(1^\omega)(2)(1,1)(2,2,1^\omega)=Y(1,3,4,2,5,6,4,9)</math>
+* <math>(0)(1^\omega)(2)(1,1)(2,2,1^\omega)(3)=Y(1,3,4,2,5,6,4,9,10)</math>
+* <math>(0)(1^\omega)(2)(1,1)(2,2,1^\omega)(3)(2,2)=Y(1,3,4,2,5,6,4,9,10,7)</math>
+* <math>(0)(1^\omega)(2)(1,1)(2,2,1^\omega)(3)(2,2)(3,3,1^\omega)(4)=Y(1,3,4,2,5,6,4,9,10,7,13,14)</math>
+* <math>(0)(1^\omega)(2)(1,1,1)=Y(1,3,4,2,5,6,4,9,10,8)</math>
+* <math>(0)(1^\omega)(2)(1,1,1)(2,2,2,1)=Y(1,3,4,2,5,6,4,9,10,8,16)</math>
+* <math>(0)(1^\omega)(2)(1,1,1)(2,2,2,1^\omega)=Y(1,3,4,2,5,6,4,9,10,8,17)</math>
+* <math>(0)(1^\omega)(2)(1,1,1)(2,2,2,1^\omega)(3)=Y(1,3,4,2,5,6,4,9,10,8,17,18)</math>
+* <math>(0)(1^\omega)(2)(1,1,1)(2,2,2,1^\omega)(3)(2,2,2)=Y(1,3,4,2,5,6,4,9,10,8,17,18,15)</math>
+* <math>(0)(1^\omega)(2)(1,1,1,1)=Y(1,3,4,2,5,6,4,9,10,8,17,18,16)</math>
+* <math>(0)(1^\omega)(2)(1^\omega)=Y(1,3,4,2,5,6,5)</math>
+* <math>(0)(1^\omega)(2)(1^\omega)(2)=Y(1,3,4,2,5,6,5,6)</math>
+* <math>(0)(1^\omega)(2)(2)=Y(1,3,4,2,5,6,6)</math>
+* <math>(0)(1^\omega)(2)(3,1)=Y(1,3,4,2,5,6,8)</math>
+* <math>(0)(1^\omega)(2)(3,1,1)=Y(1,3,4,2,5,6,8,12)</math>
+* <math>(0)(1^\omega)(2)(3,1^\omega)=Y(1,3,4,2,5,6,9)</math>
+* <math>(0)(1^\omega)(2)(3,1^\omega)(4)=Y(1,3,4,2,5,6,9,10)</math>
+* <math>(0)(1^\omega)(2)(3,1^\omega)(4)(5,1^\omega)=Y(1,3,4,2,5,6,9,10,13)</math>
+* <math>(0)(1^\omega)(2,1)=Y(1,3,4,2,5,7)</math>
-\
+=== Part 3 ===
+* <math>(0)(1^\omega)(2,1)(1)=Y(1,3,4,2,5,7,2)</math>
+* <math>(0)(1^\omega)(2,1)(1)(2,1^\omega)=Y(1,3,4,2,5,7,2,5)
 后续分析参见[[Y序列 VS TBMS Part2]]、[[Y序列 VS TBMS Part3]]
 [[分类:分析]]